Base | Representation |
---|---|
bin | 10010111111110001111… |
… | …100111001100001100111 |
3 | 11121210112222001202012011 |
4 | 102333301330321201213 |
5 | 132342012144122012 |
6 | 2435412552535051 |
7 | 163212611003254 |
oct | 22776174714147 |
9 | 4553488052164 |
10 | 1305434364007 |
11 | 4636a4736314 |
12 | 1910033b1487 |
13 | 96142c39a47 |
14 | 4727d1d842b |
15 | 23e5607c1a7 |
hex | 12ff1f39867 |
1305434364007 has 2 divisors, whose sum is σ = 1305434364008. Its totient is φ = 1305434364006.
The previous prime is 1305434363993. The next prime is 1305434364061. The reversal of 1305434364007 is 7004634345031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1305434364007 - 27 = 1305434363879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305434314007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652717182003 + 652717182004.
It is an arithmetic number, because the mean of its divisors is an integer number (652717182004).
Almost surely, 21305434364007 is an apocalyptic number.
1305434364007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305434364007 is an equidigital number, since it uses as much as digits as its factorization.
1305434364007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 40.
The spelling of 1305434364007 in words is "one trillion, three hundred five billion, four hundred thirty-four million, three hundred sixty-four thousand, seven".
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