Base | Representation |
---|---|
bin | 1011110111110111100000… |
… | …0100111001011001011011 |
3 | 1201012222201222122012110012 |
4 | 2331331320010321121123 |
5 | 3202340423030142024 |
6 | 43433041241312135 |
7 | 2515102462345256 |
oct | 275757004713133 |
9 | 51188658565405 |
10 | 13054420162139 |
11 | 4183391943004 |
12 | 156a04aa9564b |
13 | 7390463ca2a5 |
14 | 331ba17dc09d |
15 | 1798970e950e |
hex | bdf7813965b |
13054420162139 has 2 divisors, whose sum is σ = 13054420162140. Its totient is φ = 13054420162138.
The previous prime is 13054420162111. The next prime is 13054420162151. The reversal of 13054420162139 is 93126102445031.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (93126102445031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13054420162139 - 240 = 11954908534363 is a prime.
It is a super-2 number, since 2×130544201621392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13054420162096 and 13054420162105.
It is not a weakly prime, because it can be changed into another prime (13054420162109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527210081069 + 6527210081070.
It is an arithmetic number, because the mean of its divisors is an integer number (6527210081070).
Almost surely, 213054420162139 is an apocalyptic number.
13054420162139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13054420162139 is an equidigital number, since it uses as much as digits as its factorization.
13054420162139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
The spelling of 13054420162139 in words is "thirteen trillion, fifty-four billion, four hundred twenty million, one hundred sixty-two thousand, one hundred thirty-nine".
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