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13054431052567 is a prime number
BaseRepresentation
bin1011110111110111100010…
…1110011100001100010111
31201012222202202010111022101
42331331320232130030113
53202340433322140232
643433042310542531
72515102654043632
oct275757056341427
951188682114271
1013054431052567
114183398001163
12156a052667a47
13739048741228
14331ba3034c19
1517989804b1e7
hexbdf78b9c317

13054431052567 has 2 divisors, whose sum is σ = 13054431052568. Its totient is φ = 13054431052566.

The previous prime is 13054431052519. The next prime is 13054431052577. The reversal of 13054431052567 is 76525013445031.

It is a strong prime.

It is an emirp because it is prime and its reverse (76525013445031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13054431052567 - 235 = 13020071314199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13054431052577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527215526283 + 6527215526284.

It is an arithmetic number, because the mean of its divisors is an integer number (6527215526284).

Almost surely, 213054431052567 is an apocalyptic number.

13054431052567 is a deficient number, since it is larger than the sum of its proper divisors (1).

13054431052567 is an equidigital number, since it uses as much as digits as its factorization.

13054431052567 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 46.

Adding to 13054431052567 its reverse (76525013445031), we get a palindrome (89579444497598).

The spelling of 13054431052567 in words is "thirteen trillion, fifty-four billion, four hundred thirty-one million, fifty-two thousand, five hundred sixty-seven".