Base | Representation |
---|---|
bin | 10010111111110010111… |
… | …000101010100100100111 |
3 | 11121210121001112201210221 |
4 | 102333302320222210213 |
5 | 132342030202001044 |
6 | 2435414312425211 |
7 | 163213161115633 |
oct | 22776270524447 |
9 | 4553531481727 |
10 | 1305450031399 |
11 | 463702567478 |
12 | 1910086a8207 |
13 | 961462640a7 |
14 | 47281315dc3 |
15 | 23e57624484 |
hex | 12ff2e2a927 |
1305450031399 has 2 divisors, whose sum is σ = 1305450031400. Its totient is φ = 1305450031398.
The previous prime is 1305450031363. The next prime is 1305450031433. The reversal of 1305450031399 is 9931300545031.
It is a strong prime.
It is an emirp because it is prime and its reverse (9931300545031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1305450031399 - 217 = 1305449900327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1305450031349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652725015699 + 652725015700.
It is an arithmetic number, because the mean of its divisors is an integer number (652725015700).
Almost surely, 21305450031399 is an apocalyptic number.
1305450031399 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305450031399 is an equidigital number, since it uses as much as digits as its factorization.
1305450031399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 218700, while the sum is 43.
The spelling of 1305450031399 in words is "one trillion, three hundred five billion, four hundred fifty million, thirty-one thousand, three hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •