Base | Representation |
---|---|
bin | 11000010100010000… |
… | …00110111010110111 |
3 | 1020200210220112022012 |
4 | 30022020012322313 |
5 | 203214012041133 |
6 | 5555225354435 |
7 | 641336652032 |
oct | 141210067267 |
9 | 36623815265 |
10 | 13054799543 |
11 | 559a104135 |
12 | 2644038a1b |
13 | 130084a876 |
14 | 8bbb52019 |
15 | 516178b48 |
hex | 30a206eb7 |
13054799543 has 2 divisors, whose sum is σ = 13054799544. Its totient is φ = 13054799542.
The previous prime is 13054799491. The next prime is 13054799567. The reversal of 13054799543 is 34599745031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13054799543 - 212 = 13054795447 is a prime.
It is a super-2 number, since 2×130547995432 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13054799491 and 13054799500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13054799843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527399771 + 6527399772.
It is an arithmetic number, because the mean of its divisors is an integer number (6527399772).
Almost surely, 213054799543 is an apocalyptic number.
13054799543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13054799543 is an equidigital number, since it uses as much as digits as its factorization.
13054799543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2041200, while the sum is 50.
The spelling of 13054799543 in words is "thirteen billion, fifty-four million, seven hundred ninety-nine thousand, five hundred forty-three".
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