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1305494916053 is a prime number
BaseRepresentation
bin10010111111110101100…
…011111000101111010101
311121210201012000002222112
4102333311203320233111
5132342123144303203
62435422554440405
7163214244456656
oct22776543705725
94553635002875
101305494916053
11463725933a29
1219101b733105
139615264b063
144728727b52d
1523e5b53d6d8
hex12ff58f8bd5

1305494916053 has 2 divisors, whose sum is σ = 1305494916054. Its totient is φ = 1305494916052.

The previous prime is 1305494916043. The next prime is 1305494916071. The reversal of 1305494916053 is 3506194945031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1075945649284 + 229549266769 = 1037278^2 + 479113^2 .

It is an emirp because it is prime and its reverse (3506194945031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1305494916053 - 210 = 1305494915029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1305494915992 and 1305494916010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1305494916043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652747458026 + 652747458027.

It is an arithmetic number, because the mean of its divisors is an integer number (652747458027).

Almost surely, 21305494916053 is an apocalyptic number.

It is an amenable number.

1305494916053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1305494916053 is an equidigital number, since it uses as much as digits as its factorization.

1305494916053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1749600, while the sum is 50.

The spelling of 1305494916053 in words is "one trillion, three hundred five billion, four hundred ninety-four million, nine hundred sixteen thousand, fifty-three".