Base | Representation |
---|---|
bin | 10010111111110101111… |
… | …001001101010000101011 |
3 | 11121210201120112001202102 |
4 | 102333311321031100223 |
5 | 132342131112131011 |
6 | 2435423314324015 |
7 | 163214343125444 |
oct | 22776571152053 |
9 | 4553646461672 |
10 | 1305500505131 |
11 | 4637290010a9 |
12 | 19102158960b |
13 | 96153856cc4 |
14 | 47287cd42cb |
15 | 23e5bc9473b |
hex | 12ff5e4d42b |
1305500505131 has 2 divisors, whose sum is σ = 1305500505132. Its totient is φ = 1305500505130.
The previous prime is 1305500505091. The next prime is 1305500505143. The reversal of 1305500505131 is 1315050055031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1305500505131 - 234 = 1288320635947 is a prime.
It is a super-2 number, since 2×13055005051312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1305500505094 and 1305500505103.
It is not a weakly prime, because it can be changed into another prime (1305500505161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652750252565 + 652750252566.
It is an arithmetic number, because the mean of its divisors is an integer number (652750252566).
Almost surely, 21305500505131 is an apocalyptic number.
1305500505131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1305500505131 is an equidigital number, since it uses as much as digits as its factorization.
1305500505131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5625, while the sum is 29.
The spelling of 1305500505131 in words is "one trillion, three hundred five billion, five hundred million, five hundred five thousand, one hundred thirty-one".
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