Base | Representation |
---|---|
bin | 111100110010101100… |
… | …1001010101100111101 |
3 | 110110222021001222201101 |
4 | 1321211121022230331 |
5 | 4114331312141013 |
6 | 135550210013101 |
7 | 12301103445364 |
oct | 1714531125475 |
9 | 413867058641 |
10 | 130550115133 |
11 | 50403155839 |
12 | 21374b77191 |
13 | c406b55549 |
14 | 64665887db |
15 | 35e12ca8dd |
hex | 1e6564ab3d |
130550115133 has 2 divisors, whose sum is σ = 130550115134. Its totient is φ = 130550115132.
The previous prime is 130550115121. The next prime is 130550115173. The reversal of 130550115133 is 331511055031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95334590169 + 35215524964 = 308763^2 + 187658^2 .
It is a cyclic number.
It is not a de Polignac number, because 130550115133 - 221 = 130548017981 is a prime.
It is a super-3 number, since 3×1305501151333 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130550115173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65275057566 + 65275057567.
It is an arithmetic number, because the mean of its divisors is an integer number (65275057567).
Almost surely, 2130550115133 is an apocalyptic number.
It is an amenable number.
130550115133 is a deficient number, since it is larger than the sum of its proper divisors (1).
130550115133 is an equidigital number, since it uses as much as digits as its factorization.
130550115133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3375, while the sum is 28.
The spelling of 130550115133 in words is "one hundred thirty billion, five hundred fifty million, one hundred fifteen thousand, one hundred thirty-three".
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