Base | Representation |
---|---|
bin | 111100110010110000… |
… | …0111010000010110001 |
3 | 110110222101220001212102 |
4 | 1321211200322002301 |
5 | 4114332322102144 |
6 | 135550321310145 |
7 | 12301126625525 |
oct | 1714540720261 |
9 | 413871801772 |
10 | 130552144049 |
11 | 50404311128 |
12 | 21375795355 |
13 | c4073b5ba2 |
14 | 6466955d85 |
15 | 35e157bb4e |
hex | 1e6583a0b1 |
130552144049 has 2 divisors, whose sum is σ = 130552144050. Its totient is φ = 130552144048.
The previous prime is 130552144027. The next prime is 130552144061. The reversal of 130552144049 is 940441255031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113757798400 + 16794345649 = 337280^2 + 129593^2 .
It is a cyclic number.
It is not a de Polignac number, because 130552144049 - 224 = 130535366833 is a prime.
It is a super-2 number, since 2×1305521440492 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130552144649) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276072024 + 65276072025.
It is an arithmetic number, because the mean of its divisors is an integer number (65276072025).
Almost surely, 2130552144049 is an apocalyptic number.
It is an amenable number.
130552144049 is a deficient number, since it is larger than the sum of its proper divisors (1).
130552144049 is an equidigital number, since it uses as much as digits as its factorization.
130552144049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 130552144049 in words is "one hundred thirty billion, five hundred fifty-two million, one hundred forty-four thousand, forty-nine".
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