Base | Representation |
---|---|
bin | 111100110010110010… |
… | …0001000110101100101 |
3 | 110110222110111002202211 |
4 | 1321211210020311211 |
5 | 4114333031203302 |
6 | 135550351403421 |
7 | 12301140054145 |
oct | 1714544106545 |
9 | 413873432684 |
10 | 130552991077 |
11 | 5040483a553 |
12 | 21375b23571 |
13 | c4076215a2 |
14 | 6466ad6925 |
15 | 35e1697ad7 |
hex | 1e65908d65 |
130552991077 has 2 divisors, whose sum is σ = 130552991078. Its totient is φ = 130552991076.
The previous prime is 130552991071. The next prime is 130552991081. The reversal of 130552991077 is 770199255031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 107111543841 + 23441447236 = 327279^2 + 153106^2 .
It is a cyclic number.
It is not a de Polignac number, because 130552991077 - 219 = 130552466789 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130552991077.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130552991071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276495538 + 65276495539.
It is an arithmetic number, because the mean of its divisors is an integer number (65276495539).
Almost surely, 2130552991077 is an apocalyptic number.
It is an amenable number.
130552991077 is a deficient number, since it is larger than the sum of its proper divisors (1).
130552991077 is an equidigital number, since it uses as much as digits as its factorization.
130552991077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 595350, while the sum is 49.
The spelling of 130552991077 in words is "one hundred thirty billion, five hundred fifty-two million, nine hundred ninety-one thousand, seventy-seven".
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