Base | Representation |
---|---|
bin | 111100110010110010… |
… | …0101000101000110011 |
3 | 110110222110201201110001 |
4 | 1321211210220220303 |
5 | 4114333044340311 |
6 | 135550354250431 |
7 | 12301141135663 |
oct | 1714544505063 |
9 | 413873651401 |
10 | 130553121331 |
11 | 504049193a6 |
12 | 21375b86a17 |
13 | c407668969 |
14 | 6466b2c1a3 |
15 | 35e16c14c1 |
hex | 1e65928a33 |
130553121331 has 2 divisors, whose sum is σ = 130553121332. Its totient is φ = 130553121330.
The previous prime is 130553121319. The next prime is 130553121353. The reversal of 130553121331 is 133121355031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130553121331 - 211 = 130553119283 is a prime.
It is a super-2 number, since 2×1305531213312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130553121331.
It is not a weakly prime, because it can be changed into another prime (130553121131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65276560665 + 65276560666.
It is an arithmetic number, because the mean of its divisors is an integer number (65276560666).
Almost surely, 2130553121331 is an apocalyptic number.
130553121331 is a deficient number, since it is larger than the sum of its proper divisors (1).
130553121331 is an equidigital number, since it uses as much as digits as its factorization.
130553121331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 130553121331 its reverse (133121355031), we get a palindrome (263674476362).
The spelling of 130553121331 in words is "one hundred thirty billion, five hundred fifty-three million, one hundred twenty-one thousand, three hundred thirty-one".
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