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13055325047 is a prime number
BaseRepresentation
bin11000010100010100…
…00111001101110111
31020200211220020011022
430022022013031313
5203214130400142
65555244531355
7641344301102
oct141212071567
936624806138
1013055325047
11559a432a36
122644250b5b
1313009a2b0b
148bbc4b739
1551622e6d2
hex30a287377

13055325047 has 2 divisors, whose sum is σ = 13055325048. Its totient is φ = 13055325046.

The previous prime is 13055325029. The next prime is 13055325061. The reversal of 13055325047 is 74052355031.

13055325047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (74052355031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13055325047 - 212 = 13055320951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13055324998 and 13055325016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13055325077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6527662523 + 6527662524.

It is an arithmetic number, because the mean of its divisors is an integer number (6527662524).

Almost surely, 213055325047 is an apocalyptic number.

13055325047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13055325047 is an equidigital number, since it uses as much as digits as its factorization.

13055325047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 35.

The spelling of 13055325047 in words is "thirteen billion, fifty-five million, three hundred twenty-five thousand, forty-seven".