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130554233129 is a prime number
BaseRepresentation
bin111100110010110100…
…0111000000100101001
3110110222112211012112202
41321211220320010221
54114333340430004
6135550434145545
712301153446245
oct1714550700451
9413875735482
10130554233129
1150405508741
12213764222b5
13c407967a28
146466d3b425
1535e1840b1e
hex1e65a38129

130554233129 has 2 divisors, whose sum is σ = 130554233130. Its totient is φ = 130554233128.

The previous prime is 130554233087. The next prime is 130554233153. The reversal of 130554233129 is 921332455031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124210429225 + 6343803904 = 352435^2 + 79648^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130554233129 is a prime.

It is a super-2 number, since 2×1305542331292 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130554233092 and 130554233101.

It is not a weakly prime, because it can be changed into another prime (130554233179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65277116564 + 65277116565.

It is an arithmetic number, because the mean of its divisors is an integer number (65277116565).

Almost surely, 2130554233129 is an apocalyptic number.

It is an amenable number.

130554233129 is a deficient number, since it is larger than the sum of its proper divisors (1).

130554233129 is an equidigital number, since it uses as much as digits as its factorization.

130554233129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 38.

The spelling of 130554233129 in words is "one hundred thirty billion, five hundred fifty-four million, two hundred thirty-three thousand, one hundred twenty-nine".