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13056151420511 is a prime number
BaseRepresentation
bin1011110111111101111101…
…0001000111111001011111
31201020011012122022020110122
42331333133101013321133
53202402444230424021
643433525124225155
72515163413656623
oct275773721077137
951204178266418
1013056151420511
1141840a0116051
12156a45283b1bb
13739260c9c524
14331cc76dd183
151799490c4bab
hexbdfdf447e5f

13056151420511 has 2 divisors, whose sum is σ = 13056151420512. Its totient is φ = 13056151420510.

The previous prime is 13056151420409. The next prime is 13056151420519. The reversal of 13056151420511 is 11502415165031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13056151420511 is a prime.

It is a super-2 number, since 2×130561514205112 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13056151420519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6528075710255 + 6528075710256.

It is an arithmetic number, because the mean of its divisors is an integer number (6528075710256).

Almost surely, 213056151420511 is an apocalyptic number.

13056151420511 is a deficient number, since it is larger than the sum of its proper divisors (1).

13056151420511 is an equidigital number, since it uses as much as digits as its factorization.

13056151420511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 13056151420511 its reverse (11502415165031), we get a palindrome (24558566585542).

The spelling of 13056151420511 in words is "thirteen trillion, fifty-six billion, one hundred fifty-one million, four hundred twenty thousand, five hundred eleven".