Base | Representation |
---|---|
bin | 111100110011001101… |
… | …0110011101000111101 |
3 | 110111000110110012100011 |
4 | 1321212122303220331 |
5 | 4114400213302143 |
6 | 135552022503221 |
7 | 12301402632601 |
oct | 1714632635075 |
9 | 414013405304 |
10 | 130567322173 |
11 | 50411938732 |
12 | 2137a894b11 |
13 | c40a59b622 |
14 | 6468987501 |
15 | 35e2a78e9d |
hex | 1e666b3a3d |
130567322173 has 2 divisors, whose sum is σ = 130567322174. Its totient is φ = 130567322172.
The previous prime is 130567322147. The next prime is 130567322243. The reversal of 130567322173 is 371223765031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130406209924 + 161112249 = 361118^2 + 12693^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130567322173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130567322113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65283661086 + 65283661087.
It is an arithmetic number, because the mean of its divisors is an integer number (65283661087).
Almost surely, 2130567322173 is an apocalyptic number.
It is an amenable number.
130567322173 is a deficient number, since it is larger than the sum of its proper divisors (1).
130567322173 is an equidigital number, since it uses as much as digits as its factorization.
130567322173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 158760, while the sum is 40.
The spelling of 130567322173 in words is "one hundred thirty billion, five hundred sixty-seven million, three hundred twenty-two thousand, one hundred seventy-three".
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