Base | Representation |
---|---|
bin | 1011111000001100101110… |
… | …0101011010101101101001 |
3 | 1201020112102221200001022002 |
4 | 2332003023211122231221 |
5 | 3202434104214212213 |
6 | 43435422354340345 |
7 | 2515363565511113 |
oct | 276031345325551 |
9 | 51215387601262 |
10 | 13060116163433 |
11 | 4185845109099 |
12 | 156b17a58a6b5 |
13 | 7397434c8161 |
14 | 3321820b63b3 |
15 | 179acc1d3658 |
hex | be0cb95ab69 |
13060116163433 has 2 divisors, whose sum is σ = 13060116163434. Its totient is φ = 13060116163432.
The previous prime is 13060116163399. The next prime is 13060116163453. The reversal of 13060116163433 is 33436161106031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12415101579049 + 645014584384 = 3523507^2 + 803128^2 .
It is a cyclic number.
It is not a de Polignac number, because 13060116163433 - 220 = 13060115114857 is a prime.
It is not a weakly prime, because it can be changed into another prime (13060116163453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530058081716 + 6530058081717.
It is an arithmetic number, because the mean of its divisors is an integer number (6530058081717).
Almost surely, 213060116163433 is an apocalyptic number.
It is an amenable number.
13060116163433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13060116163433 is an equidigital number, since it uses as much as digits as its factorization.
13060116163433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 38.
Adding to 13060116163433 its reverse (33436161106031), we get a palindrome (46496277269464).
The spelling of 13060116163433 in words is "thirteen trillion, sixty billion, one hundred sixteen million, one hundred sixty-three thousand, four hundred thirty-three".
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