Base | Representation |
---|---|
bin | 111100110100010011… |
… | …1101011110010110101 |
3 | 110111010000221110000011 |
4 | 1321220213223302311 |
5 | 4114434142033331 |
6 | 135555422220221 |
7 | 12302331553663 |
oct | 1715047536265 |
9 | 414100843004 |
10 | 130604252341 |
11 | 50430771932 |
12 | 2138b124671 |
13 | c41512bab4 |
14 | 646d83bc33 |
15 | 35e5e213b1 |
hex | 1e689ebcb5 |
130604252341 has 2 divisors, whose sum is σ = 130604252342. Its totient is φ = 130604252340.
The previous prime is 130604252293. The next prime is 130604252393. The reversal of 130604252341 is 143252406031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130357102500 + 247149841 = 361050^2 + 15721^2 .
It is a cyclic number.
It is not a de Polignac number, because 130604252341 - 217 = 130604121269 is a prime.
It is a super-3 number, since 3×1306042523413 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130604202341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65302126170 + 65302126171.
It is an arithmetic number, because the mean of its divisors is an integer number (65302126171).
Almost surely, 2130604252341 is an apocalyptic number.
It is an amenable number.
130604252341 is a deficient number, since it is larger than the sum of its proper divisors (1).
130604252341 is an equidigital number, since it uses as much as digits as its factorization.
130604252341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 130604252341 its reverse (143252406031), we get a palindrome (273856658372).
The spelling of 130604252341 in words is "one hundred thirty billion, six hundred four million, two hundred fifty-two thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •