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13060431222044 = 225236243035957
BaseRepresentation
bin1011111000001101111001…
…0111010001010100011100
31201020120020220111200110112
42332003132113101110130
53202440230343101134
643435513531225152
72515404442456253
oct276033627212434
951216226450415
1013060431222044
114185996a38308
12156b247ba81b8
1373979386917b
143321b1c8979a
15179ae9bb91ce
hexbe0de5d151c

13060431222044 has 12 divisors (see below), whose sum is σ = 22899455893944. Its totient is φ = 6517729538064.

The previous prime is 13060431222017. The next prime is 13060431222103. The reversal of 13060431222044 is 44022213406031.

It is a self number, because there is not a number n which added to its sum of digits gives 13060431222044.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3121515887 + ... + 3121520070.

It is an arithmetic number, because the mean of its divisors is an integer number (1908287991162).

Almost surely, 213060431222044 is an apocalyptic number.

It is an amenable number.

13060431222044 is a deficient number, since it is larger than the sum of its proper divisors (9839024671900).

13060431222044 is a wasteful number, since it uses less digits than its factorization.

13060431222044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6243036484 (or 6243036482 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13060431222044 its reverse (44022213406031), we get a palindrome (57082644628075).

The spelling of 13060431222044 in words is "thirteen trillion, sixty billion, four hundred thirty-one million, two hundred twenty-two thousand, forty-four".

Divisors: 1 2 4 523 1046 2092 6243035957 12486071914 24972143828 3265107805511 6530215611022 13060431222044