Base | Representation |
---|---|
bin | 1011111000001110010011… |
… | …1110000011110000100011 |
3 | 1201020120112122001111111222 |
4 | 2332003210332003300203 |
5 | 3202440442231202121 |
6 | 43435532530525255 |
7 | 2515410256512626 |
oct | 276034476036043 |
9 | 51216478044458 |
10 | 13060542053411 |
11 | 4185a43557586 |
12 | 156b27913682b |
13 | 7397b0802a68 |
14 | 3321c2899dbd |
15 | 179b047ad0ab |
hex | be0e4f83c23 |
13060542053411 has 2 divisors, whose sum is σ = 13060542053412. Its totient is φ = 13060542053410.
The previous prime is 13060542053359. The next prime is 13060542053423. The reversal of 13060542053411 is 11435024506031.
13060542053411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13060542053411 - 26 = 13060542053347 is a prime.
It is not a weakly prime, because it can be changed into another prime (13060542053311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530271026705 + 6530271026706.
It is an arithmetic number, because the mean of its divisors is an integer number (6530271026706).
Almost surely, 213060542053411 is an apocalyptic number.
13060542053411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13060542053411 is an equidigital number, since it uses as much as digits as its factorization.
13060542053411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13060542053411 its reverse (11435024506031), we get a palindrome (24495566559442).
The spelling of 13060542053411 in words is "thirteen trillion, sixty billion, five hundred forty-two million, fifty-three thousand, four hundred eleven".
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