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13060542053311 is a prime number
BaseRepresentation
bin1011111000001110010011…
…1110000011101110111111
31201020120112122001111101021
42332003210332003232333
53202440442231201221
643435532530525011
72515410256512424
oct276034476035677
951216478044337
1013060542053311
114185a435574a5
12156b279136767
137397b08029bc
143321c2899d4b
15179b047ad041
hexbe0e4f83bbf

13060542053311 has 2 divisors, whose sum is σ = 13060542053312. Its totient is φ = 13060542053310.

The previous prime is 13060542053269. The next prime is 13060542053347. The reversal of 13060542053311 is 11335024506031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13060542053311 - 29 = 13060542052799 is a prime.

It is a super-3 number, since 3×130605420533113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13060542053411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530271026655 + 6530271026656.

It is an arithmetic number, because the mean of its divisors is an integer number (6530271026656).

Almost surely, 213060542053311 is an apocalyptic number.

13060542053311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13060542053311 is an equidigital number, since it uses as much as digits as its factorization.

13060542053311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 13060542053311 its reverse (11335024506031), we get a palindrome (24395566559342).

The spelling of 13060542053311 in words is "thirteen trillion, sixty billion, five hundred forty-two million, fifty-three thousand, three hundred eleven".