Base | Representation |
---|---|
bin | 1011111000001110010011… |
… | …1110000011101110111111 |
3 | 1201020120112122001111101021 |
4 | 2332003210332003232333 |
5 | 3202440442231201221 |
6 | 43435532530525011 |
7 | 2515410256512424 |
oct | 276034476035677 |
9 | 51216478044337 |
10 | 13060542053311 |
11 | 4185a435574a5 |
12 | 156b279136767 |
13 | 7397b08029bc |
14 | 3321c2899d4b |
15 | 179b047ad041 |
hex | be0e4f83bbf |
13060542053311 has 2 divisors, whose sum is σ = 13060542053312. Its totient is φ = 13060542053310.
The previous prime is 13060542053269. The next prime is 13060542053347. The reversal of 13060542053311 is 11335024506031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13060542053311 - 29 = 13060542052799 is a prime.
It is a super-3 number, since 3×130605420533113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13060542053411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530271026655 + 6530271026656.
It is an arithmetic number, because the mean of its divisors is an integer number (6530271026656).
Almost surely, 213060542053311 is an apocalyptic number.
13060542053311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13060542053311 is an equidigital number, since it uses as much as digits as its factorization.
13060542053311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 13060542053311 its reverse (11335024506031), we get a palindrome (24395566559342).
The spelling of 13060542053311 in words is "thirteen trillion, sixty billion, five hundred forty-two million, fifty-three thousand, three hundred eleven".
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