Base | Representation |
---|---|
bin | 10011000000010110111… |
… | …100100010011100000111 |
3 | 11121212011012221122222122 |
4 | 103000112330202130013 |
5 | 132344300041321224 |
6 | 2435554323520155 |
7 | 163234155360602 |
oct | 23002674423407 |
9 | 4555135848878 |
10 | 1306055026439 |
11 | 463993017179 |
12 | 19115722905b |
13 | 962116bb417 |
14 | 472db7dd339 |
15 | 23e907cc15e |
hex | 13016f22707 |
1306055026439 has 2 divisors, whose sum is σ = 1306055026440. Its totient is φ = 1306055026438.
The previous prime is 1306055026433. The next prime is 1306055026447. The reversal of 1306055026439 is 9346205506031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1306055026439 - 212 = 1306055022343 is a prime.
It is a super-3 number, since 3×13060550264393 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1306055026439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1306055026433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653027513219 + 653027513220.
It is an arithmetic number, because the mean of its divisors is an integer number (653027513220).
Almost surely, 21306055026439 is an apocalyptic number.
1306055026439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1306055026439 is an equidigital number, since it uses as much as digits as its factorization.
1306055026439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583200, while the sum is 44.
The spelling of 1306055026439 in words is "one trillion, three hundred six billion, fifty-five million, twenty-six thousand, four hundred thirty-nine".
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