Base | Representation |
---|---|
bin | 1011111000001111011100… |
… | …1000000101010110000111 |
3 | 1201020121022212020200121202 |
4 | 2332003313020011112013 |
5 | 3202442103221434424 |
6 | 43440023051533115 |
7 | 2515420645644353 |
oct | 276036710052607 |
9 | 51217285220552 |
10 | 13060846671239 |
11 | 418608a4a5454 |
12 | 156b34315a19b |
13 | 73982b9596b3 |
14 | 332211112463 |
15 | 179b213d02ae |
hex | be0f7205587 |
13060846671239 has 2 divisors, whose sum is σ = 13060846671240. Its totient is φ = 13060846671238.
The previous prime is 13060846671221. The next prime is 13060846671247. The reversal of 13060846671239 is 93217664806031.
13060846671239 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13060846671239 - 236 = 12992127194503 is a prime.
It is a super-2 number, since 2×130608466712392 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13060846371239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530423335619 + 6530423335620.
It is an arithmetic number, because the mean of its divisors is an integer number (6530423335620).
Almost surely, 213060846671239 is an apocalyptic number.
13060846671239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13060846671239 is an equidigital number, since it uses as much as digits as its factorization.
13060846671239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7838208, while the sum is 56.
The spelling of 13060846671239 in words is "thirteen trillion, sixty billion, eight hundred forty-six million, six hundred seventy-one thousand, two hundred thirty-nine".
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