Base | Representation |
---|---|
bin | 1011111000001111011100… |
… | …1000000101011101110011 |
3 | 1201020121022212020201021222 |
4 | 2332003313020011131303 |
5 | 3202442103221443411 |
6 | 43440023051535255 |
7 | 2515420645645655 |
oct | 276036710053563 |
9 | 51217285221258 |
10 | 13060846671731 |
11 | 418608a4a5861 |
12 | 156b34315a52b |
13 | 73982b9599a1 |
14 | 3322111126d5 |
15 | 179b213d04db |
hex | be0f7205773 |
13060846671731 has 2 divisors, whose sum is σ = 13060846671732. Its totient is φ = 13060846671730.
The previous prime is 13060846671721. The next prime is 13060846671751. The reversal of 13060846671731 is 13717664806031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13060846671731 is a prime.
It is a super-4 number, since 4×130608466717314 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13060846671721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6530423335865 + 6530423335866.
It is an arithmetic number, because the mean of its divisors is an integer number (6530423335866).
Almost surely, 213060846671731 is an apocalyptic number.
13060846671731 is a deficient number, since it is larger than the sum of its proper divisors (1).
13060846671731 is an equidigital number, since it uses as much as digits as its factorization.
13060846671731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 13060846671731 in words is "thirteen trillion, sixty billion, eight hundred forty-six million, six hundred seventy-one thousand, seven hundred thirty-one".
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