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130615511245421 is a prime number
BaseRepresentation
bin11101101100101101001011…
…001001100110001001101101
3122010110201110120000020211012
4131230231023021212021231
5114110001031334323141
61141443534300035005
736340442063030366
oct3554551311461155
9563421416006735
10130615511245421
11386887aaa60014
12127961b2532a65
1357b5cb3950207
142437b78508b6d
151017921065ceb
hex76cb4b26626d

130615511245421 has 2 divisors, whose sum is σ = 130615511245422. Its totient is φ = 130615511245420.

The previous prime is 130615511245369. The next prime is 130615511245463. The reversal of 130615511245421 is 124542115516031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101364342096196 + 29251169149225 = 10067986^2 + 5408435^2 .

It is a cyclic number.

It is not a de Polignac number, because 130615511245421 - 210 = 130615511244397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130615511245481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65307755622710 + 65307755622711.

It is an arithmetic number, because the mean of its divisors is an integer number (65307755622711).

Almost surely, 2130615511245421 is an apocalyptic number.

It is an amenable number.

130615511245421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130615511245421 is an equidigital number, since it uses as much as digits as its factorization.

130615511245421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 41.

The spelling of 130615511245421 in words is "one hundred thirty trillion, six hundred fifteen billion, five hundred eleven million, two hundred forty-five thousand, four hundred twenty-one".