Base | Representation |
---|---|
bin | 10011000000100011001… |
… | …111001101111111101111 |
3 | 11121212200120222220120110 |
4 | 103000203033031333233 |
5 | 132400210340000111 |
6 | 2440031011551103 |
7 | 163242241265553 |
oct | 23004317157757 |
9 | 4555616886513 |
10 | 1306261250031 |
11 | 463a8946aaa1 |
12 | 1911b42bb493 |
13 | 9624534440a |
14 | 4731ad61863 |
15 | 23ea39655a6 |
hex | 130233cdfef |
1306261250031 has 4 divisors (see below), whose sum is σ = 1741681666712. Its totient is φ = 870840833352.
The previous prime is 1306261250029. The next prime is 1306261250053. The reversal of 1306261250031 is 1300521626031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1306261250031 - 21 = 1306261250029 is a prime.
It is a super-2 number, since 2×13062612500312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1306261250431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 217710208336 + ... + 217710208341.
It is an arithmetic number, because the mean of its divisors is an integer number (435420416678).
Almost surely, 21306261250031 is an apocalyptic number.
1306261250031 is a deficient number, since it is larger than the sum of its proper divisors (435420416681).
1306261250031 is an equidigital number, since it uses as much as digits as its factorization.
1306261250031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 435420416680.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 1306261250031 its reverse (1300521626031), we get a palindrome (2606782876062).
The spelling of 1306261250031 in words is "one trillion, three hundred six billion, two hundred sixty-one million, two hundred fifty thousand, thirty-one".
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