Base | Representation |
---|---|
bin | 111100110101000110… |
… | …0011000011010011111 |
3 | 110111011212121120002211 |
4 | 1321222030120122133 |
5 | 4120012421241003 |
6 | 140002204101251 |
7 | 12303102125434 |
oct | 1715214303237 |
9 | 414155546084 |
10 | 130630649503 |
11 | 50444661472 |
12 | 21397b34827 |
13 | c41a741c13 |
14 | 647314db8b |
15 | 35e83d796d |
hex | 1e6a31869f |
130630649503 has 2 divisors, whose sum is σ = 130630649504. Its totient is φ = 130630649502.
The previous prime is 130630649491. The next prime is 130630649537. The reversal of 130630649503 is 305946036031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130630649503 - 213 = 130630641311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130630649803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65315324751 + 65315324752.
It is an arithmetic number, because the mean of its divisors is an integer number (65315324752).
Almost surely, 2130630649503 is an apocalyptic number.
130630649503 is a deficient number, since it is larger than the sum of its proper divisors (1).
130630649503 is an equidigital number, since it uses as much as digits as its factorization.
130630649503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 40.
The spelling of 130630649503 in words is "one hundred thirty billion, six hundred thirty million, six hundred forty-nine thousand, five hundred three".
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