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13065024433997 is a prime number
BaseRepresentation
bin1011111000011111000000…
…1000111110111101001101
31201021000010000110000201202
42332013300020332331031
53203024132223341442
643441553411515245
72515626325230614
oct276076010767515
951230100400652
1013065024433997
114187933763448
12157010a2b8b25
1373a04634a873
143324c9cda87b
15179cb806ac32
hexbe1f023ef4d

13065024433997 has 2 divisors, whose sum is σ = 13065024433998. Its totient is φ = 13065024433996.

The previous prime is 13065024433973. The next prime is 13065024434009. The reversal of 13065024433997 is 79933442056031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9084955543876 + 3980068890121 = 3014126^2 + 1995011^2 .

It is a cyclic number.

It is not a de Polignac number, because 13065024433997 - 242 = 8666977922893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13065024433597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6532512216998 + 6532512216999.

It is an arithmetic number, because the mean of its divisors is an integer number (6532512216999).

Almost surely, 213065024433997 is an apocalyptic number.

It is an amenable number.

13065024433997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13065024433997 is an equidigital number, since it uses as much as digits as its factorization.

13065024433997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14696640, while the sum is 56.

The spelling of 13065024433997 in words is "thirteen trillion, sixty-five billion, twenty-four million, four hundred thirty-three thousand, nine hundred ninety-seven".