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130654777481 is a prime number
BaseRepresentation
bin111100110101110100…
…0011011000010001001
3110111020120000101110122
41321223220123002021
54120040110334411
6140004425153025
712303514166414
oct1715350330211
9414216011418
10130654777481
1150457241148
12213a402b775
13c42273c227
146476430b7b
1535ea5a19db
hex1e6ba1b089

130654777481 has 2 divisors, whose sum is σ = 130654777482. Its totient is φ = 130654777480.

The previous prime is 130654777439. The next prime is 130654777549. The reversal of 130654777481 is 184777456031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122279599225 + 8375178256 = 349685^2 + 91516^2 .

It is a cyclic number.

It is not a de Polignac number, because 130654777481 - 230 = 129581035657 is a prime.

It is a super-2 number, since 2×1306547774812 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (130654777381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65327388740 + 65327388741.

It is an arithmetic number, because the mean of its divisors is an integer number (65327388741).

Almost surely, 2130654777481 is an apocalyptic number.

It is an amenable number.

130654777481 is a deficient number, since it is larger than the sum of its proper divisors (1).

130654777481 is an equidigital number, since it uses as much as digits as its factorization.

130654777481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3951360, while the sum is 53.

The spelling of 130654777481 in words is "one hundred thirty billion, six hundred fifty-four million, seven hundred seventy-seven thousand, four hundred eighty-one".