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130670447777 is a prime number
BaseRepresentation
bin111100110110010010…
…0001100110010100001
3110111021122111112001222
41321230210030302201
54120103113312102
6140010145104425
712304064323412
oct1715444146241
9414248445058
10130670447777
1150465074501
12213a9328115
13c425a679ac
14647854d809
1535ebb49aa2
hex1e6c90cca1

130670447777 has 2 divisors, whose sum is σ = 130670447778. Its totient is φ = 130670447776.

The previous prime is 130670447749. The next prime is 130670447801. The reversal of 130670447777 is 777744076031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130087176976 + 583270801 = 360676^2 + 24151^2 .

It is a cyclic number.

It is not a de Polignac number, because 130670447777 - 226 = 130603338913 is a prime.

It is not a weakly prime, because it can be changed into another prime (130670447737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65335223888 + 65335223889.

It is an arithmetic number, because the mean of its divisors is an integer number (65335223889).

Almost surely, 2130670447777 is an apocalyptic number.

It is an amenable number.

130670447777 is a deficient number, since it is larger than the sum of its proper divisors (1).

130670447777 is an equidigital number, since it uses as much as digits as its factorization.

130670447777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4840416, while the sum is 53.

The spelling of 130670447777 in words is "one hundred thirty billion, six hundred seventy million, four hundred forty-seven thousand, seven hundred seventy-seven".