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130683114637 is a prime number
BaseRepresentation
bin111100110110101010…
…0100001010010001101
3110111022112100001201221
41321231110201102031
54120114334132022
6140011320403341
712304310101135
oct1715524412215
9414275301657
10130683114637
1150471236289
12213b1616551
13c42858138a
14647a0c9ac5
1535ecceccc7
hex1e6d52148d

130683114637 has 2 divisors, whose sum is σ = 130683114638. Its totient is φ = 130683114636.

The previous prime is 130683114619. The next prime is 130683114659. The reversal of 130683114637 is 736411386031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114123028041 + 16560086596 = 337821^2 + 128686^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130683114637 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130683114593 and 130683114602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130683114607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65341557318 + 65341557319.

It is an arithmetic number, because the mean of its divisors is an integer number (65341557319).

Almost surely, 2130683114637 is an apocalyptic number.

It is an amenable number.

130683114637 is a deficient number, since it is larger than the sum of its proper divisors (1).

130683114637 is an equidigital number, since it uses as much as digits as its factorization.

130683114637 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 130683114637 in words is "one hundred thirty billion, six hundred eighty-three million, one hundred fourteen thousand, six hundred thirty-seven".