Base | Representation |
---|---|
bin | 1011111000110101101011… |
… | …0111010001100110100011 |
3 | 1201021120211010100210210012 |
4 | 2332031122313101212203 |
5 | 3203124113114434222 |
6 | 43444441320555135 |
7 | 2516233201065023 |
oct | 276153267214643 |
9 | 51246733323705 |
10 | 13071109921187 |
11 | 418a476872aaa |
12 | 1571328322aab |
13 | 73a7a6048466 |
14 | 3329061dda83 |
15 | 17a02243d1e2 |
hex | be35add19a3 |
13071109921187 has 2 divisors, whose sum is σ = 13071109921188. Its totient is φ = 13071109921186.
The previous prime is 13071109921141. The next prime is 13071109921189. The reversal of 13071109921187 is 78112990117031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13071109921187 - 212 = 13071109917091 is a prime.
Together with 13071109921189, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13071109921189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6535554960593 + 6535554960594.
It is an arithmetic number, because the mean of its divisors is an integer number (6535554960594).
Almost surely, 213071109921187 is an apocalyptic number.
13071109921187 is a deficient number, since it is larger than the sum of its proper divisors (1).
13071109921187 is an equidigital number, since it uses as much as digits as its factorization.
13071109921187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 190512, while the sum is 50.
The spelling of 13071109921187 in words is "thirteen trillion, seventy-one billion, one hundred nine million, nine hundred twenty-one thousand, one hundred eighty-seven".
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