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1307204113153 is a prime number
BaseRepresentation
bin10011000001011011011…
…011111101001100000001
311121222010022011022121211
4103001123123331030001
5132404123223110103
62440304332450121
7163304510425621
oct23013333751401
94558108138554
101307204113153
11464422709014
12191418019941
13963657978a3
14473aa278881
152400b60c36d
hex1305b6fd301

1307204113153 has 2 divisors, whose sum is σ = 1307204113154. Its totient is φ = 1307204113152.

The previous prime is 1307204113151. The next prime is 1307204113157. The reversal of 1307204113153 is 3513114027031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 906423955969 + 400780157184 = 952063^2 + 633072^2 .

It is a cyclic number.

It is not a de Polignac number, because 1307204113153 - 21 = 1307204113151 is a prime.

Together with 1307204113151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1307204113151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653602056576 + 653602056577.

It is an arithmetic number, because the mean of its divisors is an integer number (653602056577).

Almost surely, 21307204113153 is an apocalyptic number.

It is an amenable number.

1307204113153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1307204113153 is an equidigital number, since it uses as much as digits as its factorization.

1307204113153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7560, while the sum is 31.

The spelling of 1307204113153 in words is "one trillion, three hundred seven billion, two hundred four million, one hundred thirteen thousand, one hundred fifty-three".