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13074128233553 is a prime number
BaseRepresentation
bin1011111001000000111011…
…0001001110010001010001
31201021212121110211221222002
42332100032301032101101
53203201303311433203
643450101021523345
72516401041240362
oct276201661162121
951255543757862
1013074128233553
114190785600832
121571a2b113555
1373ab67471bca
14332b11011b69
1517a14c3ecd88
hexbe40ec4e451

13074128233553 has 2 divisors, whose sum is σ = 13074128233554. Its totient is φ = 13074128233552.

The previous prime is 13074128233549. The next prime is 13074128233561. The reversal of 13074128233553 is 35533282147031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10620246712384 + 2453881521169 = 3258872^2 + 1566487^2 .

It is a cyclic number.

It is not a de Polignac number, because 13074128233553 - 22 = 13074128233549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13074128233498 and 13074128233507.

It is not a weakly prime, because it can be changed into another prime (13074128233513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6537064116776 + 6537064116777.

It is an arithmetic number, because the mean of its divisors is an integer number (6537064116777).

Almost surely, 213074128233553 is an apocalyptic number.

It is an amenable number.

13074128233553 is a deficient number, since it is larger than the sum of its proper divisors (1).

13074128233553 is an equidigital number, since it uses as much as digits as its factorization.

13074128233553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 47.

The spelling of 13074128233553 in words is "thirteen trillion, seventy-four billion, one hundred twenty-eight million, two hundred thirty-three thousand, five hundred fifty-three".