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1307435181413 is a prime number
BaseRepresentation
bin10011000001101001001…
…101011010010101100101
311121222201101221210200112
4103001221031122111211
5132410111401301123
62440343305222405
7163313314451204
oct23015115322545
94558641853615
101307435181413
11464531091019
12191481491a05
13963a160c17a
14473ccc2723b
1524021a51d78
hex1306935a565

1307435181413 has 2 divisors, whose sum is σ = 1307435181414. Its totient is φ = 1307435181412.

The previous prime is 1307435181407. The next prime is 1307435181427. The reversal of 1307435181413 is 3141815347031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 678089665444 + 629345515969 = 823462^2 + 793313^2 .

It is an emirp because it is prime and its reverse (3141815347031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1307435181413 - 24 = 1307435181397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1307435181473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 653717590706 + 653717590707.

It is an arithmetic number, because the mean of its divisors is an integer number (653717590707).

Almost surely, 21307435181413 is an apocalyptic number.

It is an amenable number.

1307435181413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1307435181413 is an equidigital number, since it uses as much as digits as its factorization.

1307435181413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 1307435181413 in words is "one trillion, three hundred seven billion, four hundred thirty-five million, one hundred eighty-one thousand, four hundred thirteen".