Base | Representation |
---|---|
bin | 10011000010100101011… |
… | …111000101110001011011 |
3 | 11122002022212211111122122 |
4 | 103002211133011301123 |
5 | 132414144242324411 |
6 | 2441031512211455 |
7 | 163350344210342 |
oct | 23024537056133 |
9 | 4562285744578 |
10 | 1308446448731 |
11 | 4649aaa00134 |
12 | 191704099b8b |
13 | 96502c929b6 |
14 | 47487268b59 |
15 | 2408070b9db |
hex | 130a57c5c5b |
1308446448731 has 2 divisors, whose sum is σ = 1308446448732. Its totient is φ = 1308446448730.
The previous prime is 1308446448719. The next prime is 1308446448739. The reversal of 1308446448731 is 1378446448031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1308446448731 - 214 = 1308446432347 is a prime.
It is a super-2 number, since 2×13084464487312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1308446448739) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654223224365 + 654223224366.
It is an arithmetic number, because the mean of its divisors is an integer number (654223224366).
Almost surely, 21308446448731 is an apocalyptic number.
1308446448731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1308446448731 is an equidigital number, since it uses as much as digits as its factorization.
1308446448731 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6193152, while the sum is 53.
The spelling of 1308446448731 in words is "one trillion, three hundred eight billion, four hundred forty-six million, four hundred forty-eight thousand, seven hundred thirty-one".
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