Base | Representation |
---|---|
bin | 1011111001110011001000… |
… | …0011011100010101000011 |
3 | 1201100011101200222102122222 |
4 | 2332130302003130111003 |
5 | 3203411403402123204 |
6 | 43500210210121255 |
7 | 2520356024651501 |
oct | 276346203342503 |
9 | 51304350872588 |
10 | 13087605114179 |
11 | 4196470991702 |
12 | 157457058022b |
13 | 73c20459279b |
14 | 33362cc35671 |
15 | 17a68a64cabe |
hex | be7320dc543 |
13087605114179 has 2 divisors, whose sum is σ = 13087605114180. Its totient is φ = 13087605114178.
The previous prime is 13087605114163. The next prime is 13087605114197. The reversal of 13087605114179 is 97141150678031.
13087605114179 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (13087605114197) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13087605114179 - 24 = 13087605114163 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13087605114179.
It is not a weakly prime, because it can be changed into another prime (13087605114149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6543802557089 + 6543802557090.
It is an arithmetic number, because the mean of its divisors is an integer number (6543802557090).
Almost surely, 213087605114179 is an apocalyptic number.
13087605114179 is a deficient number, since it is larger than the sum of its proper divisors (1).
13087605114179 is an equidigital number, since it uses as much as digits as its factorization.
13087605114179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1270080, while the sum is 53.
The spelling of 13087605114179 in words is "thirteen trillion, eighty-seven billion, six hundred five million, one hundred fourteen thousand, one hundred seventy-nine".
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