Base | Representation |
---|---|
bin | 10011000010111010100… |
… | …110010000100110001101 |
3 | 11122010020120022202220211 |
4 | 103002322212100212031 |
5 | 132420410431241423 |
6 | 2441131004042421 |
7 | 163362204652102 |
oct | 23027246204615 |
9 | 4563216282824 |
10 | 1308800649613 |
11 | 465071934536 |
12 | 1917a2833411 |
13 | 9655b48a012 |
14 | 474bc30aaa9 |
15 | 240a187510d |
hex | 130ba99098d |
1308800649613 has 2 divisors, whose sum is σ = 1308800649614. Its totient is φ = 1308800649612.
The previous prime is 1308800649601. The next prime is 1308800649643. The reversal of 1308800649613 is 3169460088031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 751087422409 + 557713227204 = 866653^2 + 746802^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1308800649613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1308800649643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654400324806 + 654400324807.
It is an arithmetic number, because the mean of its divisors is an integer number (654400324807).
Almost surely, 21308800649613 is an apocalyptic number.
It is an amenable number.
1308800649613 is a deficient number, since it is larger than the sum of its proper divisors (1).
1308800649613 is an equidigital number, since it uses as much as digits as its factorization.
1308800649613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 49.
The spelling of 1308800649613 in words is "one trillion, three hundred eight billion, eight hundred million, six hundred forty-nine thousand, six hundred thirteen".
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