Base | Representation |
---|---|
bin | 10011000011000011000… |
… | …110111101101100000001 |
3 | 11122010121112000022101102 |
4 | 103003003012331230001 |
5 | 132421204010100031 |
6 | 2441153104344145 |
7 | 163365560445344 |
oct | 23030306755401 |
9 | 4563545008342 |
10 | 1308943440641 |
11 | 4651354a2551 |
12 | 191822615055 |
13 | 96581c33855 |
14 | 474d327a45b |
15 | 240ae17d7cb |
hex | 130c31bdb01 |
1308943440641 has 2 divisors, whose sum is σ = 1308943440642. Its totient is φ = 1308943440640.
The previous prime is 1308943440613. The next prime is 1308943440647. The reversal of 1308943440641 is 1460443498031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 966947722225 + 341995718416 = 983335^2 + 584804^2 .
It is a cyclic number.
It is not a de Polignac number, because 1308943440641 - 26 = 1308943440577 is a prime.
It is not a weakly prime, because it can be changed into another prime (1308943440647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654471720320 + 654471720321.
It is an arithmetic number, because the mean of its divisors is an integer number (654471720321).
Almost surely, 21308943440641 is an apocalyptic number.
It is an amenable number.
1308943440641 is a deficient number, since it is larger than the sum of its proper divisors (1).
1308943440641 is an equidigital number, since it uses as much as digits as its factorization.
1308943440641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 995328, while the sum is 47.
The spelling of 1308943440641 in words is "one trillion, three hundred eight billion, nine hundred forty-three million, four hundred forty thousand, six hundred forty-one".
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