13092941573681 has 2 divisors, whose sum is σ = 13092941573682. Its totient is φ = 13092941573680.

The previous prime is 13092941573629. The next prime is 13092941573683. The reversal of 13092941573681 is 18637514929031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7626655489600 + 5466286084081 = 2761640^2 + 2338009^2 .

It is a cyclic number.

It is not a de Polignac number, because 13092941573681 - 2³⁰ = 13091867831857 is a prime.

It is a super-3 number, since 3×13092941573681³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13092941573683, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13092941573681.

It is not a weakly prime, because it can be changed into another prime (13092941573683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6546470786840 + 6546470786841.

It is an arithmetic number, because the mean of its divisors is an integer number (6546470786841).

It is a 1-persistent number, because it is pandigital, but 2⋅13092941573681 = 26185883147362 is not.

Almost surely, 2^{13092941573681} is an apocalyptic number.

It is an amenable number.

13092941573681 is a deficient number, since it is larger than the sum of its proper divisors (1).

13092941573681 is an equidigital number, since it uses as much as digits as its factorization.

13092941573681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 59.

The spelling of 13092941573681 in words is "thirteen trillion, ninety-two billion, nine hundred forty-one million, five hundred seventy-three thousand, six hundred eighty-one".