Base | Representation |
---|---|
bin | 1111100110111… |
… | …01001100011001 |
3 | 100010100220102021 |
4 | 13303131030121 |
5 | 232004220213 |
6 | 20554134441 |
7 | 3146611315 |
oct | 763351431 |
9 | 303326367 |
10 | 130929433 |
11 | 679a7248 |
12 | 37a21421 |
13 | 2118284b |
14 | 13562b45 |
15 | b763d8d |
hex | 7cdd319 |
130929433 has 2 divisors, whose sum is σ = 130929434. Its totient is φ = 130929432.
The previous prime is 130929419. The next prime is 130929473. The reversal of 130929433 is 334929031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86266944 + 44662489 = 9288^2 + 6683^2 .
It is an emirp because it is prime and its reverse (334929031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130929433 - 25 = 130929401 is a prime.
It is a super-3 number, since 3×1309294333 (a number of 25 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (130929473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65464716 + 65464717.
It is an arithmetic number, because the mean of its divisors is an integer number (65464717).
Almost surely, 2130929433 is an apocalyptic number.
It is an amenable number.
130929433 is a deficient number, since it is larger than the sum of its proper divisors (1).
130929433 is an equidigital number, since it uses as much as digits as its factorization.
130929433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 34.
The square root of 130929433 is about 11442.4399932881. The cubic root of 130929433 is about 507.7840974467.
The spelling of 130929433 in words is "one hundred thirty million, nine hundred twenty-nine thousand, four hundred thirty-three".
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