Base | Representation |
---|---|
bin | 111100111110000010… |
… | …0101100111101011101 |
3 | 110111221210001222001011 |
4 | 1321330010230331131 |
5 | 4121121220021042 |
6 | 140052041415221 |
7 | 12313403650564 |
oct | 1717404547535 |
9 | 414853058034 |
10 | 130930626397 |
11 | 50588a1a55a |
12 | 2146049a511 |
13 | c46793233c |
14 | 64a0d18bdb |
15 | 36148dea17 |
hex | 1e7c12cf5d |
130930626397 has 2 divisors, whose sum is σ = 130930626398. Its totient is φ = 130930626396.
The previous prime is 130930626373. The next prime is 130930626473. The reversal of 130930626397 is 793626039031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 66587738116 + 64342888281 = 258046^2 + 253659^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130930626397 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130930626397.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130930626347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65465313198 + 65465313199.
It is an arithmetic number, because the mean of its divisors is an integer number (65465313199).
Almost surely, 2130930626397 is an apocalyptic number.
It is an amenable number.
130930626397 is a deficient number, since it is larger than the sum of its proper divisors (1).
130930626397 is an equidigital number, since it uses as much as digits as its factorization.
130930626397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1102248, while the sum is 49.
The spelling of 130930626397 in words is "one hundred thirty billion, nine hundred thirty million, six hundred twenty-six thousand, three hundred ninety-seven".
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