Base | Representation |
---|---|
bin | 10011000011011111001… |
… | …011101111011001101011 |
3 | 11122011211100022022110122 |
4 | 103003133023233121223 |
5 | 132423140100024031 |
6 | 2441311532033455 |
7 | 163413340136624 |
oct | 23033713573153 |
9 | 4564740268418 |
10 | 1309414454891 |
11 | 465357361524 |
12 | 19193430288b |
13 | 966286aa4ca |
14 | 47539a48a4b |
15 | 240da6bd47b |
hex | 130df2ef66b |
1309414454891 has 2 divisors, whose sum is σ = 1309414454892. Its totient is φ = 1309414454890.
The previous prime is 1309414454839. The next prime is 1309414454897. The reversal of 1309414454891 is 1984544149031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1309414454891 is a prime.
It is a super-3 number, since 3×13094144548913 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1309414454897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654707227445 + 654707227446.
It is an arithmetic number, because the mean of its divisors is an integer number (654707227446).
Almost surely, 21309414454891 is an apocalyptic number.
1309414454891 is a deficient number, since it is larger than the sum of its proper divisors (1).
1309414454891 is an equidigital number, since it uses as much as digits as its factorization.
1309414454891 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2488320, while the sum is 53.
The spelling of 1309414454891 in words is "one trillion, three hundred nine billion, four hundred fourteen million, four hundred fifty-four thousand, eight hundred ninety-one".
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