Base | Representation |
---|---|
bin | 111100111111111011… |
… | …0011110111111110001 |
3 | 110112010012100002022202 |
4 | 1321333312132333301 |
5 | 4121233431224144 |
6 | 140102224112545 |
7 | 12315103461002 |
oct | 1717766367761 |
9 | 415105302282 |
10 | 130994008049 |
11 | 50610780093 |
12 | 21479765755 |
13 | c477ac4588 |
14 | 64a94d71a9 |
15 | 361a25e64e |
hex | 1e7fd9eff1 |
130994008049 has 2 divisors, whose sum is σ = 130994008050. Its totient is φ = 130994008048.
The previous prime is 130994008031. The next prime is 130994008099. The reversal of 130994008049 is 940800499031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118804302400 + 12189705649 = 344680^2 + 110407^2 .
It is a cyclic number.
It is not a de Polignac number, because 130994008049 - 224 = 130977230833 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130994007994 and 130994008012.
It is not a weakly prime, because it can be changed into another prime (130994008099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65497004024 + 65497004025.
It is an arithmetic number, because the mean of its divisors is an integer number (65497004025).
Almost surely, 2130994008049 is an apocalyptic number.
It is an amenable number.
130994008049 is a deficient number, since it is larger than the sum of its proper divisors (1).
130994008049 is an equidigital number, since it uses as much as digits as its factorization.
130994008049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 47.
The spelling of 130994008049 in words is "one hundred thirty billion, nine hundred ninety-four million, eight thousand, forty-nine".
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