Base | Representation |
---|---|
bin | 1011111010100001010011… |
… | …1110001110101010101111 |
3 | 1201101100101200010002002001 |
4 | 2332220110332032222233 |
5 | 3204112301020011002 |
6 | 43510020300513131 |
7 | 2521305156456022 |
oct | 276502476165257 |
9 | 51340350102061 |
10 | 13100002110127 |
11 | 41a07527471a9 |
12 | 1576a5024b7a7 |
13 | 74042ba5644a |
14 | 3340874751b9 |
15 | 17ab63b8ba87 |
hex | bea14f8eaaf |
13100002110127 has 2 divisors, whose sum is σ = 13100002110128. Its totient is φ = 13100002110126.
The previous prime is 13100002110077. The next prime is 13100002110211. The reversal of 13100002110127 is 72101120000131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13100002110127 is a prime.
It is a super-2 number, since 2×131000021101272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100002114127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550001055063 + 6550001055064.
It is an arithmetic number, because the mean of its divisors is an integer number (6550001055064).
Almost surely, 213100002110127 is an apocalyptic number.
13100002110127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100002110127 is an equidigital number, since it uses as much as digits as its factorization.
13100002110127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 13100002110127 its reverse (72101120000131), we get a palindrome (85201122110258).
The spelling of 13100002110127 in words is "thirteen trillion, one hundred billion, two million, one hundred ten thousand, one hundred twenty-seven".
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