Base | Representation |
---|---|
bin | 1011111010100001010100… |
… | …0110010110111110111110 |
3 | 1201101100101211010100112221 |
4 | 2332220111012112332332 |
5 | 3204112302041210332 |
6 | 43510020414315554 |
7 | 2521305213543334 |
oct | 276502506267676 |
9 | 51340354110487 |
10 | 13100004241342 |
11 | 41a0753972437 |
12 | 1576a50ab8bba |
13 | 74042c321515 |
14 | 33408786bb54 |
15 | 17ab63e5d297 |
hex | bea15196fbe |
13100004241342 has 8 divisors (see below), whose sum is σ = 19898740620000. Its totient is φ = 6467090701344.
The previous prime is 13100004241327. The next prime is 13100004241343. The reversal of 13100004241342 is 24314240000131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×131000042413422 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100004241343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41455709467 + ... + 41455709782.
It is an arithmetic number, because the mean of its divisors is an integer number (2487342577500).
Almost surely, 213100004241342 is an apocalyptic number.
13100004241342 is a deficient number, since it is larger than the sum of its proper divisors (6798736378658).
13100004241342 is an equidigital number, since it uses as much as digits as its factorization.
13100004241342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82911419330.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13100004241342 its reverse (24314240000131), we get a palindrome (37414244241473).
The spelling of 13100004241342 in words is "thirteen trillion, one hundred billion, four million, two hundred forty-one thousand, three hundred forty-two".
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