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13100004241342 = 27982911419249
BaseRepresentation
bin1011111010100001010100…
…0110010110111110111110
31201101100101211010100112221
42332220111012112332332
53204112302041210332
643510020414315554
72521305213543334
oct276502506267676
951340354110487
1013100004241342
1141a0753972437
121576a50ab8bba
1374042c321515
1433408786bb54
1517ab63e5d297
hexbea15196fbe

13100004241342 has 8 divisors (see below), whose sum is σ = 19898740620000. Its totient is φ = 6467090701344.

The previous prime is 13100004241327. The next prime is 13100004241343. The reversal of 13100004241342 is 24314240000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×131000042413422 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100004241343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41455709467 + ... + 41455709782.

It is an arithmetic number, because the mean of its divisors is an integer number (2487342577500).

Almost surely, 213100004241342 is an apocalyptic number.

13100004241342 is a deficient number, since it is larger than the sum of its proper divisors (6798736378658).

13100004241342 is an equidigital number, since it uses as much as digits as its factorization.

13100004241342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82911419330.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13100004241342 its reverse (24314240000131), we get a palindrome (37414244241473).

The spelling of 13100004241342 in words is "thirteen trillion, one hundred billion, four million, two hundred forty-one thousand, three hundred forty-two".

Divisors: 1 2 79 158 82911419249 165822838498 6550002120671 13100004241342