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13100010000223 is a prime number
BaseRepresentation
bin1011111010100001010101…
…1100010100111101011111
31201101100102012221221020211
42332220111130110331133
53204112310030001343
643510021141553251
72521305313520146
oct276502534247537
951340365857224
1013100010000223
1141a0757146143
121576a52a15827
13740430589843
1433408852a75d
1517ab646e979d
hexbea15714f5f

13100010000223 has 2 divisors, whose sum is σ = 13100010000224. Its totient is φ = 13100010000222.

The previous prime is 13100010000199. The next prime is 13100010000229. The reversal of 13100010000223 is 32200001000131.

It is a strong prime.

It is an emirp because it is prime and its reverse (32200001000131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100010000223 is a prime.

It is a super-2 number, since 2×131000100002232 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100010000229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550005000111 + 6550005000112.

It is an arithmetic number, because the mean of its divisors is an integer number (6550005000112).

Almost surely, 213100010000223 is an apocalyptic number.

13100010000223 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100010000223 is an equidigital number, since it uses as much as digits as its factorization.

13100010000223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13100010000223 its reverse (32200001000131), we get a palindrome (45300011000354).

The spelling of 13100010000223 in words is "thirteen trillion, one hundred billion, ten million, two hundred twenty-three", and thus it is an aban number.