Base | Representation |
---|---|
bin | 11101110010010011010111… |
… | …000110011101100010101110 |
3 | 122011211111011222220112010102 |
4 | 131302103113012131202232 |
5 | 114132301211444321220 |
6 | 1142340341554311102 |
7 | 36410305610533325 |
oct | 3562232706354256 |
9 | 564744158815112 |
10 | 131000111323310 |
11 | 38816920748a59 |
12 | 12838848288492 |
13 | 581334692a4b8 |
14 | 244c6213030bc |
15 | 102293099e775 |
hex | 7724d719d8ae |
131000111323310 has 16 divisors (see below), whose sum is σ = 235832277809952. Its totient is φ = 52392916212000.
The previous prime is 131000111323229. The next prime is 131000111323349. The reversal of 131000111323310 is 13323111000131.
It is a super-2 number, since 2×1310001113233102 (a number of 29 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 890962481 + ... + 891109500.
It is an arithmetic number, because the mean of its divisors is an integer number (14739517363122).
Almost surely, 2131000111323310 is an apocalyptic number.
131000111323310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131000111323310 is a deficient number, since it is larger than the sum of its proper divisors (104832166486642).
131000111323310 is a wasteful number, since it uses less digits than its factorization.
131000111323310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1782079339.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 131000111323310 its reverse (13323111000131), we get a palindrome (144323222323441).
The spelling of 131000111323310 in words is "one hundred thirty-one trillion, one hundred eleven million, three hundred twenty-three thousand, three hundred ten".
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