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1310001114040 = 23532750027851
BaseRepresentation
bin10011000100000010001…
…001101010101110111000
311122020100020012200112021
4103010002021222232320
5132430340241122130
62441450050124224
7163434022513303
oct23040211525670
94566306180467
101310001114040
114656285281a3
12191a78880674
13966c00b49b8
144759391bb3a
1524121e5337a
hex1310226abb8

1310001114040 has 16 divisors (see below), whose sum is σ = 2947502506680. Its totient is φ = 524000445600.

The previous prime is 1310001114013. The next prime is 1310001114193. The reversal of 1310001114040 is 404111000131.

It is a super-2 number, since 2×13100011140402 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16375013886 + ... + 16375013965.

Almost surely, 21310001114040 is an apocalyptic number.

1310001114040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310001114040 is an abundant number, since it is smaller than the sum of its proper divisors (1637501392640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310001114040 is a wasteful number, since it uses less digits than its factorization.

1310001114040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32750027862 (or 32750027858 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 1310001114040 its reverse (404111000131), we get a palindrome (1714112114171).

The spelling of 1310001114040 in words is "one trillion, three hundred ten billion, one million, one hundred fourteen thousand, forty".

Divisors: 1 2 4 5 8 10 20 40 32750027851 65500055702 131000111404 163750139255 262000222808 327500278510 655000557020 1310001114040