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131000120222 = 265500060111
BaseRepresentation
bin111101000000000110…
…1110011001110011110
3110112010121211121122112
41322000031303032132
54121242012321342
6140103003114022
712315206435516
oct1720015631636
9415117747575
10131000120222
1150614175274
122147b812912
13c47915464a
1464aa248846
15361aa6a682
hex1e8037339e

131000120222 has 4 divisors (see below), whose sum is σ = 196500180336. Its totient is φ = 65500060110.

The previous prime is 131000120219. The next prime is 131000120281. The reversal of 131000120222 is 222021000131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1310001202222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000120197 and 131000120206.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750030054 + ... + 32750030057.

It is an arithmetic number, because the mean of its divisors is an integer number (49125045084).

Almost surely, 2131000120222 is an apocalyptic number.

131000120222 is a deficient number, since it is larger than the sum of its proper divisors (65500060114).

131000120222 is an equidigital number, since it uses as much as digits as its factorization.

131000120222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65500060113.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 131000120222 its reverse (222021000131), we get a palindrome (353021120353).

The spelling of 131000120222 in words is "one hundred thirty-one billion, one hundred twenty thousand, two hundred twenty-two".

Divisors: 1 2 65500060111 131000120222