Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …010000111011000010011 |
3 | 11122020100020102122111011 |
4 | 103010002022013120103 |
5 | 132430340303401004 |
6 | 2441450052431351 |
7 | 163434023512351 |
oct | 23040212073023 |
9 | 4566306378434 |
10 | 1310001231379 |
11 | 4656285a8375 |
12 | 191a78918557 |
13 | 966c0126229 |
14 | 4759394c7d1 |
15 | 24121e78004 |
hex | 13102287613 |
1310001231379 has 2 divisors, whose sum is σ = 1310001231380. Its totient is φ = 1310001231378.
The previous prime is 1310001231373. The next prime is 1310001231401. The reversal of 1310001231379 is 9731321000131.
It is a weak prime.
It is an emirp because it is prime and its reverse (9731321000131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310001231379 - 231 = 1307853747731 is a prime.
It is a super-2 number, since 2×13100012313792 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1310001231379.
It is not a weakly prime, because it can be changed into another prime (1310001231373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655000615689 + 655000615690.
It is an arithmetic number, because the mean of its divisors is an integer number (655000615690).
Almost surely, 21310001231379 is an apocalyptic number.
1310001231379 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310001231379 is an equidigital number, since it uses as much as digits as its factorization.
1310001231379 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402, while the sum is 31.
The spelling of 1310001231379 in words is "one trillion, three hundred ten billion, one million, two hundred thirty-one thousand, three hundred seventy-nine".
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